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authorRich Felker <dalias@aerifal.cx>2014-12-18 17:41:34 -0500
committerRich Felker <dalias@aerifal.cx>2014-12-18 17:41:34 -0500
commit0f859fc99325bbb25d506b28565e4a7385ffe0e6 (patch)
treea069484f168c2667b8dca5c2231023a15be87a4c
parent2e1ae3b6b9331383ba5eaa7cb47373a8bea073d1 (diff)
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don't suppress sign output for NANs in printf
formally, it seems a sign is only required when the '+' modifier appears in the format specifier, in which case either '+' or '-' must be present in the output. but the specification is written such that an optional negative sign is part of the output format anyway, and the simplest approach to fixing the problem is removing the code that was suppressing the sign.
-rw-r--r--src/stdio/vfprintf.c2
1 files changed, 1 insertions, 1 deletions
diff --git a/src/stdio/vfprintf.c b/src/stdio/vfprintf.c
index d421817c..2ecf7692 100644
--- a/src/stdio/vfprintf.c
+++ b/src/stdio/vfprintf.c
@@ -225,7 +225,7 @@ static int fmt_fp(FILE *f, long double y, int w, int p, int fl, int t)
if (!isfinite(y)) {
char *s = (t&32)?"inf":"INF";
- if (y!=y) s=(t&32)?"nan":"NAN", pl=0;
+ if (y!=y) s=(t&32)?"nan":"NAN";
pad(f, ' ', w, 3+pl, fl&~ZERO_PAD);
out(f, prefix, pl);
out(f, s, 3);